50 mL of HCl is titrated with a solution of .24 M NaOH. It requires 35mL of NaOH to reach the equivalence point. What is the concentration (M) of the HCl solution?
50 mL of HCl is titrated with a solution of .24 M NaOH. It requires 35mL of NaOH to reach the equiva
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Posted 1 month ago #
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Normality (N) = n x Molarity (M), where n, the number of displaceable H+ or OH-, is one in this case.
Therefore use N1V1 = N2V2 to calculate the Normality or Molarity of HCl needed to reach the equivalence point.
(0.24N NaOH) x (35 mL NaOH) = (N of HCl) x (50mL HCl)
The concentration of the HCl solution is approximately 0.17 N or 0.17 M.Posted 1 month ago #
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